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This will give you $x'(t)$ in terms of the other constants and the function $y(t)$, but in order to integrate this (i.e. You cannot solve one equation for two variables, so it is impossible to solve this (Mathematica or otherwise) without more information.Īs a third alternative, if you are trying to rearrange this equation without solving the differential equation, you can do that: Solve + b(y-y0)=0,x'] From the documentation (Solve::ifun): 'Inverse functions normally give one branch of a general inverse, so equations that are solved in terms of inverse functions may omit solutions associated with other branches. Your system seems to refer to two functions, x(t) and y(t). begingroup This is that the solution are computed using inverse functions. If you have a more complicated function in mind, then it might make sense to use an NDSolve approach instead, but you will need to provide such an example before I show that approach. That will give you a function (in terms of constants $a,b,y_0$) that is the answer, and it will include the unspecified constant of integration. #How to use wolfram mathematica to solve functions codeThese notebooks provide the complete code used to generate the results on the poster 'Solving the Quintic with Mathematica.' quintic equation, polynomials, small degree polynomials, solving polynomials, Tschirnhauss transformation, Kleins approach to the quintic, quadratic. Mathematica has a built-in differential-equation solver: DSolve + b (y - y0) = 0, y, t] For the newest resources, visit Wolfram Repositories and Archives ». That is not the same as "rearranging a function y=f into x=g" because there are derivatives involved. Still, within Mathematica 10 there are plenty of spectacular new things that will be possible by using just small amounts of data from the Wolfram Knowledgebase. Now, the equation you give is a differential equation. But since that’s not the typical use of Mathematica, basic versions of Mathematica 10 are just set up for small-scale data accessand need explicit Wolfram Cloud Credits to get more. There are two functions given, and the domain of each is only for y>=7/4. It would be easy to substitute a value for x now, but you still have the constant C 1 because you have not provided initial conditions yet. Solving equations yields a solution for the. However, even here you should notice that inverse functions are not necessarily unique. Algebraic equations consist of two mathematical quantities, such as polynomials, being equated to each other. There are two or three different problems here that you might be asking:įirst, if you really do have a function f defined and you want to rearrange it, you would be doing something like this: f=2+x+x^2
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